ASTR 498N Lecture
10 Thermodynamics
(online at www.astro.umd.edu/~drabin/)
If you can’t take the heat,
Get out of the skillet.
Because the beautiful and intricate subject of thermodynamics is covered by a number of good texts, it’s understandable that astronomy books tend to bring in thermodynamic results on an ad hoc basis, as needed. Unfortunately, this often leads to a disjointed and confusing treatment. Let’s recall some basic results of thermodynamics in a more systematic way.
Macroscopic systems
The macroscopic quantities that characterize a thermodynamic system are called state quantities: they include internal energy U, volume V, entropy S, particle number N (in the case of a single type of particle), temperature T, pressure P, chemical potential μ, and possibly other quantities such as applied magnetic or electric fields.
The quantities U, V, S, and N are extensive (global): if you subdivide a homogeneous part of the system in half, the value of any of these quantities splits equally between the halves. On the other hand, T, P, and μ are intensive (local): they have the same values in either half.
First and second laws of thermodynamics
The first law of thermodynamics, applied to any infinitesimal process, states that
where the work done by the system is and the heat
δQ absorbed by the system is defined by this relationship. The infinitesimal quantities δW and δQ are not
exact differentials because work and heat are not state functions: the work done by the system in going between
two states depends on how the transition is made, and similarly for the heat
absorbed by the system.
The second law of thermodynamics states that, for a quasi-static (reversible) infinitesimal process, there exist macroscopic parameters S (entropy) and T (absolute temperature) such that
Fundamental relationship for internal energy
Combining the above statements of the first and second laws gives a fundamental relationship of thermodynamics,
This relationship
describes the change in internal energy of the system when the extensive
quantities S, V, and N change under the influence of the
intensive quantities T, P, and μ. The internal energy is called a thermodynamic
potential because, if we know it as a state function of the other
extensive variables, U = U(S,V,N), we can
derive complete knowledge of the macroscopic systemnamely, the intensive quantities are obtained as
derivatives of the fundamental relationship with respect to the extensive
variables:
and
and
These derivative
equations are known as equations of state. So, for example, the middle equation above yields for an ideal
gas. Note that, unlike a state function
such as U(S,V,N),
a single equation of state like P(T,V,N)
does not carry complete information about the system. If we know all the independent equations of state, we can
recover the state function by integration.
We say “independent
equations of state” because not all the intensive variables are
independent. This can be understood in
the following way. The ratio of two
extensive variables is intensive. Only
two independent intensive variables can be constructed from the three extensive
variables S, V, and Ne.g., S/V and N/V. Any other intensive ratio (such as S/N)
can be derived from these two ratios.
We can derive a useful relationship by formalizing this reasoning. All the quantities in the state function U(S,V,N) are extensive. So, if we change (say, increase) the volume from V to αV, S becomes αV, N becomes αN, and U becomes αU. That is,
This contrasts with the behavior of an intensive variable such as temperature, for which
Now let α be an infinitesimal increase, , and Taylor-expand U:
which requires by inspection that
Now substitute for the partial derivatives from the equations of state above to find
which is sometimes called Euler’s equation. The total differential of Euler’s equation is just
which, when compared with the fundamental relationship , requires
and shows explicity how only two of the three intensive variables T, P, and μ can be chosen independently (this is known as the Gibbs-Duhem relation). By the same token, only two of the three equations of state are independent.
Other thermodynamic potentials
Although the state function U(S,V,N)
basically “says it all,” the state variables S, V, and N
are not always the most convenient. In
many laboratory settings, it is easier to control an intensive variable such as
T or P. In the context of
stars, we may want to work with particular variables because they appear, for
example, in the stellar structure equations.
Are there other state functionsfor example, a state function depending on T,
P, and N? Remember, not
just any function of these variables will preserve complete information about
the system and thereby qualify as a state function.
It is shown in thermodynamics texts that three other
thermodynamic potentials can be derived from U(S,V,N)
by Legendre transformations. To each
thermodynamic potential there corresponds a fundamental relationship analogous
to .
It would take us too far afield to derive all the transformations, but we want to collect them (generalized to more than one species of particle) and show you a mnemonic device for remembering all the thermodynamic relationships when the particle numbers do not vary.
The thermodynamic potentials and their natural independent variables are
Equations of state can be read off from the fundamental relationships just as illustrated above for internal energy. For example, in the case of the Gibbs free energy,
and
and
where the notation signifies
the derivative with all variables except Ni kept
constant. Note that, when there is only
one species of particle, G = μN and the Gibbs free energy per
particle is identical with the chemical potential.
Maxwell relations
Returning to our old friends, the equations of state for U(S,V,N),
and
and
we notice that we can exploit the fact that the second derivatives of U must be independent of the order in which the derivatives are taken. For example,
from which it follows that
Another example, involving a particle species, would be
These cross-derivative relations are called Maxwell relations. It’s evident that we can derive a bewildering number of them. How can we call to mind a particular relation when we want it?
The thermodynamic square

The mnemonic for drawing the square is: “To Verify Fundamental Thermodynamics, Get Powerful Help From Square’s Extremities.” The “To” reminds you first to draw an arrow toward a corner of the square. Then, start labeling from that corner around the square using the first letter of each word (“V”, “F”, “T”, “G”, “P”, “H”) until you hit “From,” at which point you draw an arrow away from the next corner. Then fill in the last two quantities from the first letters of the last two words, “S” and “E”. The only catch is that we are using “U” instead of “E” for the internal energy. You can use E as long as you remember what it is.
Now that we’ve drawn the square, what use is it?
1. The thermodynamic potentials U, F, G, and H are along the edges.
2. Each potential is flanked by its natural variables; for example, H is flanked by S and P.
3.
You can extract the fundamental relationship for each
potential from the corners opposite the natural variables. To continue with the H example: since H = H(S,P), the
fundamental relationship will have the form . Since T is opposite S and the
arrow is pointing toward T, fill in T before dS; likewise
for V in front of dP. The
result is
.
As a second example, the square indicates that . S is opposite T but the arrow
is pointing away from S, so fill in
S. V is opposite P and the arrow
is pointing toward P, so fill in V. The result is
.
4.
You can read off the equations of state for each
potential. For example, the derivative
of F with respect to V is given by the variable diagonally across from V, with
a negative sign because the arrow is pointing away from that variablei.e.,
. As another example,
.
5.
Finally, you can extract any of the Maxwell relations by
matching pairs of variables in adjacent corners with their counterparts on the
opposite side of the square. For
example, S and P will be matched with V and T in
the sense that will be equated with
.
will be taken at constant T because
the arrow from S points toward T.
will be taken at constant P because P
is opposite V, but a minus sign will be used because the arrow is
pointing away from P. The result
is
.
Now, ain’t that cool? Well, it is to us geeks.