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Gaussian Elimination with Backsubstitution
If, during GJE, only subtract rows below pivot, will be left with a triangular matrix:
- Solution for x3 is then trivial: x3 = b3'/a33'.
- Substitute into 2nd row to get x2.
- Substitute x3 & x2 into 1st row to get x1.
Faster than GJE, but still memory hog.